**Section 4.7

/* This is an example of using printf() function */
/* These few lines are comment to the program    */
/* The example is prepare by Nicholas & Vincent  */

int main (void)
{
        printf("Hi! How are you?\n");
        printf("Welcome to this class.n");
        return 0;
}

The result is:

Hi! How are you?
Welcome to this class.



int main (void)
{
        printf("Hi! \nHow are you?\n");
        printf("Welcome to \nthis class.n");
        return 0;
}

The result is:

Hi!
How are you?
Welcome to
this class.



/* This program demonstrates the function of printf () */

int main (void)
{
        int i = 2;
        int j = 3;

        printf("%d  and  %d",i,j);
        printf("%d  and  %d",j,i);
        return 0;
}

The result is:
                
2  and  3
3  and  2


** Section 4.8.3

/* This program demonstrates the usage of operator */
/* The command a += b  is equal to   a= a+b        */

int main (void)
{
        int i,j,k;

        i = 2;
        j = 3;
        k = 4;

        i += j;
        printf("The first result is %d\n",i);
        i -= j;
        printf("The second result is %d\n",i);
        i *= j;
        printf("The third result is %d\n",i);
        i /= j;
        printf("The forth result is %d\n",i);
        i %= j;
        printf("The fifth result is %d\n",i);

        return 0;
}

The result are:

The first result is 5
The second result is 2
The third result is 14
The forth result is 2
The fifth result is 2


** Section 4.94

/* Demonstration of the for loop  */

int main (void)
{
        int sum, i;

        sum =0;
        printf("  i     sum from 1 to i\n");
        printf(" ---    ---------------\n");
        for (i = 1 ; i <= 5; i++)
        {
                sum = sum + 1;
                printf (" %d      %d\n",i,sum);
        }
        return 0;
}

The result is:

 i     sum from 1 to i
---    ---------------
 1      1
 2      3
 3      6
 4      10
 5      15



/* The same program with while loop */

int main (void)
{
        int sum, i;

        sum =0;
        printf("  i     sum from 1 to i\n");
        printf(" ---    ---------------\n");
        while (i <= 5)
        {
                sum = sum + 1;
                printf (" %d      %d\n",i,sum);
                i++;
        }
        return 0;
}



/* The same program with do-while loop */

int main (void)
{
        int sum, i;

        sum =0;
        printf("  i     sum from 1 to i\n");
        printf(" ---    ---------------\n");
        do
        {
                sum = sum + 1;
                printf (" %d      %d\n",i,sum);
                i++;
        }while(i <= 10);
        return 0;
}



/* This program demonstrate two loops  */

int main (void)
{
        int i,j,data;
        for ( i = 1 ; i < 5 ; i ++)
        {
                for ( j = 1 ; j < 3 ; j ++)
                {
                        data = i * j;
                        printf("%d * %d = %d   ",i,j,data);
                }
                printf ("\n");
        }
        return 0;
}

The result is:

1 * 1 = 1      1 * 2 = 2       1 * 3 = 3
2 * 1 = 2      2 * 2 = 4       2 * 3 = 6
3 * 1 = 3      3 * 2 = 6       3 * 3 = 9
4 * 1 = 4      4 * 2 = 8       4 * 3 = 12
5 * 1 = 5      5 * 2 = 10      5 * 3 = 15




/* The same program with two while loops  */

int main (void)
{
        int i,j,data;
        i = 1;
        while ( i < 5 )
        {
                j = 1;
                while ( j < 3 )
                {
                        data = i * j;
                        printf("%d * %d = %d   ",i,j,data);
                        j ++;
                }
                printf ("\n");
                i ++;
        }
        return 0;
}


The result is:

1 * 1 = 1      1 * 2 = 2       1 * 3 = 3
2 * 1 = 2      2 * 2 = 4       2 * 3 = 6
3 * 1 = 3      3 * 2 = 6       3 * 3 = 9
4 * 1 = 4      4 * 2 = 8       4 * 3 = 12
5 * 1 = 5      5 * 2 = 10      5 * 3 = 15





** Section 4.9.2

/* < if - else > command                             */
/* This is a program for test odd or even number */

int main (void)
{
        int i,temp;

        printf ("Input the number by key pad \n");
        i = getnum ();    /* The function get a number from the key pad */
        temp = i % 2;     /* Find the remainder */
        if ( temp == 1)
          printf ("The number is odd \n");
        else
          printf ("The number is even \n");

        return 0;
}



** Section 4.9.6

/* < Break > instruction */
/* Test the key pad      */

int main (void)
{
        int i;
        while (1)
        {
                printf ("Press the '2' in the key pad\n");
                i = getnum();
                if (i == 2)
                   break;
        }
        printf ("The num key '2' is ok !!");
        return 0;
}


** Section 4.9.7

/* < Continue > instruction */

int main (void)
{
        int i;
        int sum = 0;

        for ( i = 1 ; i < 10 ; i ++)
        {
                if ( i == 5 )
                   continue;
                sum = sum + i;
        }
        printf ("The sum is %d.",sum);
        return 0;
}


The result is:

The sum is 50.




** Section 4.10  <<< On this section the LED program should be added  >>>

/* An example of using array */

int main (void)
{
        int i,j,temp;
        int data[5] = { 95, 50, 64, 58, 80 };

        for ( i = 0; i < 4; i++)
        {
                for ( i = 0; i < 4; i++)
                {
                        if (data[j] > data [j+1])
                        {
                          temp = data [j];
                          data [j] = data [j+1];
                          data [j+1] = temp;
                        }
                }
        }
        printf ("The arranged data is:\n");
        for ( i = 0; i < 5; i ++)
           printf ("%d\n",data [i]);
        return 0;
}


The result is:

The arranged data is:
50
58
64
80
95


** Section 4.8.5

/* The us of < or > */

int main (void)
{
        int i = 15;
        int j = 18;
        int k;

        k = i | j;
        printf ("The bitwise or of 15 and 18 is: \n");
        printf ("%d\n",k);
        return 0;
}

The result is:


The bitwise or of 15 and 18 is:
31


The operation is:

        00001111
        00010010
        ________
        00011111